1.
Using the frequency of a string equation, explain the two conditions that would cause the frequency of the small violin to be the same as the full-sized violin.
2. Sound travels at 1007 m/s in helium.
a. Your voice sounds higher after you have inhaled the helium from a party balloon. Explain why this happens using the wave formula.
b. The frequency of a Helmholtz resonator also increases if you use helium instead of air as the gas. Explain why this happens using the Helmholtz Resonator formula.
3. You are building a Monochord – a one stringed musical instrument. You use a string that is 1 mm in diameter. You then change to a string that is ¼ the diameter of the original, made of the same material, with the same tension and length.
Using the frequency of a string formula, explain why the new frequency would be 4 times the frequency of the original string.
Hint – volume of a string = area x length. Area = πr2
